SOLUTION: lydia takes 10 mins more to complete an illustration than tom. the total time taken by both of them is 6hrs. how much time did each required?

Algebra.Com
Question 305282: lydia takes 10 mins more to complete an illustration than tom. the total time taken by both of them is 6hrs. how much time did each required?
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
lydia takes 10 mins more to complete an illustration than tom.
the total time taken by both of them is 6hrs.
how much time did each required?
:
Change 6 hr to 360 minutes
:
Let t = tom's time alone (in minutes)
then
(t+10) = Lydia's time alone
:
Let the complete job = 1
:
A typical shared work equation
+ = 1
multiply equation by t(t+10), resulting in
360(t+10) + 360t = t(t+10)
:
360t + 3600 + 360t = t^2 + 10t
:
720t + 3600 = t^2 + 10t
Arrange as a quadratic equation
0 = t^2 + 10t - 720t + 3600
:
t^2 - 710t + 3600 = 0
use the quadratic formula, only one solution will be reasonable

RELATED QUESTIONS

Lydia takes ten minutes more to complete an illustration than Tom. The total time taken... (answered by Fombitz)
) Lydia takes ten minutes more to complete an illustration than Tom. The total time taken (answered by ankor@dixie-net.com)
10. Lydia takes ten minutes more to complete an illustration than Tom. The total time... (answered by stanbon)
Hello, I could really use some help on this one. Thanks! Lydia takes ten minutes more to... (answered by ankor@dixie-net.com,Shin123,MathTherapy)
lydia takes ten minutes morwe to complete an illustration than tom. the total time taken... (answered by ptaylor)
Lydia takes seven minutes more to complete an illustration than Tom. The total time taken (answered by ankor@dixie-net.com)
Translate into algebraic equations : 1- A student averages 84 on five tests. If the... (answered by ankor@dixie-net.com)
Hello Can you please help me to identify the variables, coefficients, and constants in... (answered by ankor@dixie-net.com)
A takes 12 hrs to complete a work B takes 10 hrs to complete the same work time taken by... (answered by richwmiller)