SOLUTION: Find three consecutive positive even whole number such that the sum of the square of the two smaller numbers is 20 more than the square of the largest number.
I need to set up a
Algebra.Com
Question 297368: Find three consecutive positive even whole number such that the sum of the square of the two smaller numbers is 20 more than the square of the largest number.
I need to set up an equation and solve.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
x^2+(x+2)^2=(x+4)^2+20
x^2+x^2+4x+4=x^2+8x+16+20
2x^2-x^2+4x-8x+4-16-20=0
x^2-4x-32=0
(x-8)(x+4)=0
x-8=0
x=8 ans.
8+2=10 ans.
8=4=12 ans.
Proof:
8^2+10^2=12^2+20
64+100=144+20
164=164
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