SOLUTION: Penny's bicycle trip from colorado springs to pikes peak took 1.5 hours longer than the return trip to colorado springs. if she averaged 6 mph on the way to pikes peak and 15 mph f

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: Penny's bicycle trip from colorado springs to pikes peak took 1.5 hours longer than the return trip to colorado springs. if she averaged 6 mph on the way to pikes peak and 15 mph f      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 29351: Penny's bicycle trip from colorado springs to pikes peak took 1.5 hours longer than the return trip to colorado springs. if she averaged 6 mph on the way to pikes peak and 15 mph for the return trip, then how long was the ride from Colorado springs to pikes peak?
Answer by josmiceli(6786) About Me  (Show Source):
You can put this solution on YOUR website!
d = distance from cs to pp
6 mi/hr = average rate cs to pp
15 mi/hr = average rate pp to cs
t + 1.5 = time in hours cs to pp
t = time in hours pp to cs
[1] d+=+r%5B1%5D+%2A+t%5B1%5D
[2] d+=+r%5B2%5D+%2A+t%5B2%5D
set [1] equal to [2]
6+%2A+%28t+%2B+1.5%29+=+15+%2A+t
6+%2A+t+%2B+9+=+15+%2A+t
9+=+9+%2A+t
t+=+1
t + 1.5 = time in hours cs to pp
1 + 1.5 = 2.5 hrs
check
6+%2A+2.5+=+15+%2A+1
15+=+15
OK