SOLUTION: Judy has three more dimes than nickels and twice as many nickels as quarters. If altogether she has 85 cents in nickels, dimes, and quarters, how many of each coin does she have?

Question 289408: Judy has three more dimes than nickels and twice as many nickels as quarters. If altogether she has 85 cents in nickels, dimes, and quarters, how many of each coin does she have?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Judy has three more dimes than nickels and twice as many nickels as quarters. If altogether she has 85 cents in nickels, dimes, and quarters, how many of each coin does she have?
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Equations:
d = n+3
n = 2q
5n + 10d + 25q = 85 cents
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Substitute and solve for "n"
5n + 10(n+3) + 25(n/2) = 85
Multiply thru by 2 to get:
10n + 20n + 60 + 25n = 170
55n = 110
n = 2 (# of nickels)
d = n+3 = 5 (# of dimes)
q = (1/2)n = 1 (# of quarters)
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Cheers,
Stan H.

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