SOLUTION: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?

Question 283099: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
The answer entails finding the length of the diagonal of the square "ring" which is easily accomlished using the Pythagorean theorem .
Here, a & b (the lengths of the sides of the square) = 20 feet each and c will be the length of the diagonal and thus the distance separating the two boxers when they are in their respective corners.
Substitute a = 20 and b = 20.

Take the square root of both sides.

feet.
The boxers are 28.28 feet apart.
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