SOLUTION: Four numbers have a sum of 9900. The second exceeds the first by one-seventh of the first. The third exceeds the sum of the first two by 300. The fourth exceeds the sum of the f
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Question 282713: Four numbers have a sum of 9900. The second exceeds the first by one-seventh of the first. The third exceeds the sum of the first two by 300. The fourth exceeds the sum of the first three by 300. Find the four numbers.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a+b+c+d=9900
b-a/7=a
c-300=a+b
d-300=a+b+c
a = 1050, b = 1200, c = 2550, d = 5100
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