SOLUTION: A committee at of 5 is to be formed from a group consisting of 7 Democrats, 6 Republicans, and 2 Independents.
Note: A committee is an unordered group.
(a) How many different co
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Question 282432: A committee at of 5 is to be formed from a group consisting of 7 Democrats, 6 Republicans, and 2 Independents.
Note: A committee is an unordered group.
(a) How many different committee choices are possible if there are no restrictions?
(In other words, in how many different ways can the 5 members of the committee be chosen without regard to order? Since a committee is an unordered group, this will be a combination, not a permutation.)
(b) How many committee choices are possible if the committee is to consist entirely of Democrats?
(c) How many committee choices are possible if the committee is to consist of 2 Democrats, 2 Republicans, and 1 Independent?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The number of ways to select 
things from 
things where order doesn't matter is:
\ =\ \frac{n!}{k!(n\,-\,k)!})
Part (a): Calculate \)
Part (b): Calculate \)
Part (c): Calculate \ +\ \left(6\cr 2\right)\ +\ \left(2\cr 1\right))
John
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