SOLUTION: one number is 7 less than another. if 4 times the smaller number plus 2 times the larger number is 62, find the two numbers.

Question 276710: one number is 7 less than another. if 4 times the smaller number plus 2 times the larger number is 62, find the two numbers.
Found 2 solutions by checkley77, nyc_function:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
X=Y-7
4X+2Y=62
4(Y-7)+2Y=62
4Y-28+2Y=62
6Y=62+28
6Y=90
Y=90/6
Y=15 ANS. FOR THE LARGER NUMBER.
X=15-7=8 ANS. FOR THE SMALLER NUMBER.
PROOF:
4*8+2*15=62
32+30=62
62=62

Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Let a = smaller number
Let b = larger number

4a + 2b = 62
a = b - 7
Can you take it from here? You have two equations in two unknowns.

nycfunction@yahoo.com
Guido

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