SOLUTION: Five years ago, Roma was twice as old as Joy. In 6 years, the sum of their ages will be 40 years. What is the present age of each?
Algebra.Com
Question 272669: Five years ago, Roma was twice as old as Joy. In 6 years, the sum of their ages will be 40 years. What is the present age of each?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Five years ago, Roma was twice as old as Joy. In 6 years, the sum of their ages will be 40 years. What is the present age of each?
Let joy's age be x five years ago.
Roma was 2x at that time
After 6 years joy's age will be x+11
AND Roma's age will be 2x+11
The sum will be x+11 + 2x+11 which is 40
x+11+2x+11=40
3x+22=40
3x=40-22
x=18/3
x=6 Joy's age five year ago.
Joy's age now will be 5+6 = 11 years.
Roma's age was 2*6 years five years ago
12 +5 =17 years now.
RELATED QUESTIONS
five years ago mike was twice as old as Berto.The sum of their ages in 6 years will be 40 (answered by josmiceli)
5 years ago Christian was twice as old as Alec. The sum of their ages in 6 years will be... (answered by srinivas.g)
Five years ago, a mother was twice as old as her son. In 6 years time the sum of their... (answered by Alan3354)
Five years ago, a mother was twice as old as her son. In 6 years time, the sum of the... (answered by algebrahouse.com)
Five years ago a mother was twice as old as her son in six years time the sum of their... (answered by stanbon)
The sum of mark's and joy's age is 35. 11 years ago mark was twice as old as joy is now.... (answered by lwsshak3)
Five years ago, a mother was twice as old as her son. In 6years time,the sum of their... (answered by mark_henrhiz)
In five years, Jose would be twice the age of Ana. Five years ago, Jose was four times as (answered by ankor@dixie-net.com)
in five years, Jose would be twice the age of Ana. Five years ago, Jose was 4 times as... (answered by josgarithmetic)