SOLUTION: Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet. P= 2L + 2W a) Set up an equation for the perimeter

Question 271726: Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the perimeter incolving only L, the length of the rectangle.
84=2(3-x) + 2(x)? Is this right?
b) Solove this euation algebraicall to find the length of the rectangle, Find the width as well

Found 2 solutions by dabanfield, jfulle70:
Answer by dabanfield(803) (Show Source): You can put this solution on YOUR website!
Suppose that te wideth of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 84 feet.
P= 2L + 2W
a) Set up an equation for the preimeter incolving lony L, the length of the rectangle.
84=2(3-x) + 2(x)? Is this right?
b) Solove this euation algebraicall to find the length of the rectangle, Find the width as well
You're on the right track. Since W = L-3 the second equation should be;
84 = 2*L + 2*(L-3)
Now you can solve the above for L then compute W = L-3.
Answer by jfulle70(1) (Show Source): You can put this solution on YOUR website!
84=2L+2(L-3)
84=2L+2l-6
84=4L-6
90=4L
L=22.5
w=2(22.5-3)
w=39
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