SOLUTION: I need help with this problem. A ball is thrown from the top of a roof 320 feet above the ground. The formula h=-16t^2 + 32t + 320 describes the height of the ball above the groun

Question 271091: I need help with this problem.
A ball is thrown from the top of a roof 320 feet above the ground. The formula h=-16t^2 + 32t + 320 describes the height of the ball above the ground, h, in feet, t seconds after the fall begins. I need to find the maximum height of the ball, as measured from the ground. The path of the ball is a parabola and I need to consider the vertex.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
vertex is on axis of symmetry ___ t = -32 / (2 (-16)) ___ t = 1

h = -16 + 32 + 320 = 336
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