SOLUTION: An objects altitude in meters is given by the polynomial h+vt-9.8t^2, where h is the height in meters from which the launce occurs, v is the initial upward speed in meters per seco

Question 266274: An objects altitude in meters is given by the polynomial h+vt-9.8t^2, where h is the height in meters from which the launce occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 190 m tall. If the initial speed is 40 m/sec, how high above the ground will th pebble be after 2 seconds? Round result to the nearest tenth of a meter.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h+vt-9.8t^2
h(t) = h+vt-9.8t^2
h(2) = 190 + 40*2 - 9.8*4
h(2) = 309.2 meters
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On Earth, the acceleration is 9.8 m/sec/sec
The equation should be
h(t) = h+vt - 4.9t^2

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