SOLUTION: A man spent 1/3 of his money and then lost 2/3 of the remainder. He was left with $12.00. How much did he start with?

Question 263784: A man spent 1/3 of his money and then lost 2/3 of the remainder. He was left with $12.00. How much did he start with?

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
A man spent 1/3 of his money and then lost 2/3 of the remainder. He was left with $12.00. How much did he start with?

assume he $x
spent 1/3 *x
lost 2/3 *(x- 1/3*x)
x- (1/3 *x + 2/3 * (x-1/3) *x)=12
x- (1/3*x +2/3(3x-x/3)) =12
x-(1/3 *x +4/9 *x)=12
x-((3x+4x) / 9)=12
9x-3x-4x=108
2x=108
x=54 He started with $ 54
spent 1/3 *x= $18
lost 2/3 *(x- 1/3*x) = 24
Balance =12

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