SOLUTION: City A's population is 68000, decreasing at a rate of 80 people per year. City B having population 42000 is increasing at a rate of 120 people per year. In how many years both the

Question 262971: City A's population is 68000, decreasing at a rate of 80 people per year. City B having population 42000 is increasing at a rate of 120 people per year. In how many years both the cities will have same population?
Found 2 solutions by richwmiller, sunitha.pratapani:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
68000-80x=y
42000+120x=y
x = 130, y = 57600
In 130 years They will both have 57600 people.
Answer by sunitha.pratapani(4) (Show Source): You can put this solution on YOUR website!
city A population =68000
amount of decrease =68000-80X
city B population=42000
Amount of increase=42000+120x

if both cities will have same population then
68000-80x=42000+120x
68000-42000=120x+80x
26000 = 200x
x= 26000/200
130
in 130 years both cities will have same population
check: city A population=68000-80* 130
68000-10400
57600
city B population = 42000+ 120*130
42000+15600
57600
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