# SOLUTION: 150 people attended a conference. \$4,200 was collected in registration fees. If members were charged \$25 and non-members were charged \$35, how many members attended?

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 Question 262771: 150 people attended a conference. \$4,200 was collected in registration fees. If members were charged \$25 and non-members were charged \$35, how many members attended?Answer by unlockmath(1599)   (Show Source): You can put this solution on YOUR website!Hello, We can set up 2 equations like this: Let x represent the members and y be the non-members. x+y=150 25x+35y=4200 Now, let's multiply the first equation by -25 to give us: -25x-25y=-3750 Add this to the second equation: 25x+35y=4200 And we get: 10y=450 Divide each side by 10 to get: y=45 There we go! We now know there were 45 non-members. Plug this into either original equation to find the number of members. I'll let you figure this part. Make sense? RJ Check out a new book I wrote at: www.math-unlock.com