SOLUTION: The sum of seven consecutive integers is 980. How many of them are prime?
Algebra.Com
Question 257910: The sum of seven consecutive integers is 980. How many of them are prime?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET X, X+1, X+2, X+3, X+4, X+5, X+6 BE THE 7 CONSECUTIVE INTEGERS.
X+X=1+X+2+X+3+X+4+X+5+X+6=980
7X+21=980
7X=980-21
7X=959
X=959/7
X=137 ANS. FOR THE FIRST INTEGER. PRIME
137+1=138 ANS.
137+2=139 ANS. PRIME.
137+3=140 ANS.
137+4=141 ANS.
137+5=142 ANS.
137+6=143 ANS.
PROOF:
137+138+139+140+141+142+143=980
980=980
RELATED QUESTIONS
the sum of seven consecutive integers is 980. How many of them are... (answered by josmiceli,dayne514,jgr45)
The sum of seven consecutive integers is 980. How many of them are prime? Name the prime... (answered by checkley71,Adam)
Find three consecutive positive even integers such that the sum of their squares is... (answered by Alan3354)
The sum of the squares of three consecutive even integers is 980. Find the integers.... (answered by ikleyn)
The average of seven consecutive integers is 10. What are the seven integers?
(answered by Alan3354)
The sum of four consecutive even integers is equal to seven times the first integer? What (answered by ReadingBoosters)
what is the sum of seven consecutive integers is 56. find the integers
(answered by Alan3354)
The sum of three consecutive integers is negative fifty seven. Find the... (answered by sdmmadam@yahoo.com)
the sum of three consecutive integers is negative fifty -seven. Find the integers (answered by Alan3354)