SOLUTION: Polynomials - difference of two squares The sum of the areas of two squares is 234 square inches. Each side of the larger square is five times the length of a side of the smalle

Question 257215: Polynomials - difference of two squares
The sum of the areas of two squares is 234 square inches. Each side of the larger square is five times the length of a side of the smaller square. Find the length of a side of each square.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The sum of the areas of two squares is 234 square inches.
Each side of the larger square is five times the length of a side of the smaller square.
Find the length of a side of each square.
:
Write an equation for each statement: (sides of two squares, x & y)
:
"The sum of the areas of two squares is 234 square inches."
x^2 + y^2 = 234
:
"Each side of the larger square is five times the length of a side of the smaller square."
x = 5y
:
In the 1st equation, replace x with 5y
(5y)^2 + y^2 = 234
25y^2 + y^2 = 234
26y^2 = 234
y^2 =
y^2 = 9
y = 3" side of the smaller square
then
x = 5(3) = 15" side of the larger square
:
:
Check: 15^2 + 3^2 = 234

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