SOLUTION: The sum of the first n odd positive integers is 9409. What is the value of n ?
Algebra.Com
Question 255625: The sum of the first n odd positive integers is 9409. What is the value of n ?
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Sum of 1 = 1 = 1*1 = 1^2
sum of 1 and 3 = 4 = 2*2 = 2^2
Sum of 1,3,5 = 9 = 3*3 = 3^2
and so on.
Sum of 1,3,5, . . . , n = n^2
So,
n^2 = 9409
n = 97
RELATED QUESTIONS
The sum of the first n positive odd integers is 576. What is... (answered by jim_thompson5910)
Find the sum of:
a) the first odd 'n' odd positive integers
b) the first 'n' even... (answered by Edwin McCravy)
The sum of the first m positive odd integers is 212 more than the sum of the first n... (answered by greenestamps,ikleyn)
How can I prove that for each positive integer n, the sum of the first n odd positive... (answered by tommyt3rd)
The sum of 128 consecutive odd, positive integers is the greatest power of two less than... (answered by ikleyn)
Find the sum of the first n positive... (answered by rfadrogane)
How many positive integers n < 2022 are there for which the sum of the odd positive... (answered by greenestamps)
What is the sum of the digits of the first 50 positive odd integers? (answered by Edwin McCravy)
For positive integer values of N, let N be defined as:
N = 2 + 4 + 6 + ... + N, if N (answered by Edwin McCravy)