SOLUTION: Two candles of equal length start burning at the same time. One will last 4 hours
and the other 6 hours. How many hours will they burn before one candle is twice
the length of th
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Question 255607: Two candles of equal length start burning at the same time. One will last 4 hours
and the other 6 hours. How many hours will they burn before one candle is twice
the length of the other?
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
Put this into a chart:
first . . . . .X . . . . .(3/4)X . . . . . (1/2)X . . . . (1/4)X . . . . 0X
second . . .Y . . . .(5/6)Y . . . . . . (4/6)Y . . . .(3/6)Y . . . . (2/6)Y . . . .(1/6)Y . . . . 0Y
time . . . . .0 . . . . .1 . . . . . . . . . .2 . . . . . . . . .3 . . . . . . . .. 4 . . . . . . . 5 . . . . . . .6
Notice that 2*(1/4) = 1/2. This occurs at 3 hours.
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