SOLUTION: What is the sum of the prime factors of 1998?
(A) 222 (B) 42 (C) 43 (D) 122 (E) 48
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Question 254428: What is the sum of the prime factors of 1998?
(A) 222 (B) 42 (C) 43 (D) 122 (E) 48
Found 2 solutions by richwmiller, palanisamy:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
1998=2*3*3*3*37
2,3,37
sum =42
Answer by palanisamy(496) (Show Source): You can put this solution on YOUR website!
1998 = 2*999
= 2*9*111
= 2*3*3*3*37
So the prime factors are 2,3 and 37
The sum of the prime factors = 2+3+37 = 42
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