315 = 3x3x5x7 set of prime factors = {3,5,7} (A) 15 = 3x5 set of prime factors = {3,5} (B) 21 = 3x7 set of prime factors = {3,7} (C) 35 = 5x7 set of prime factors = {5,7} (D) 105 = 3x5x7 set of prime factors = {3,5,7} (E) 125 = 5x5x5 set of prime factors = {5} Looks like (D) is the only one. Edwin