SOLUTION: Four consecutive multiples of 10 have a sum of 300. What is the least of these numbers ?
(A) 20 (B) 30 (C) 40 (D) 50 (E) 60
Algebra.Com
Question 253481: Four consecutive multiples of 10 have a sum of 300. What is the least of these numbers ?
(A) 20 (B) 30 (C) 40 (D) 50 (E) 60
Answer by vksarvepalli(154) (Show Source): You can put this solution on YOUR website!
let the no.s be 10n, 10(n+1), 10(n+2), 10(n+3)
given their sum is 300
so 10(n+n+1+n+2+n+3)=300
=> 10(4n+6)=300
=> 4n+6=30
=> 4n=24
so n=6
so the least number is 10n i.e., 60
ans: E
RELATED QUESTIONS
The average of five consecutive multiples of 5 is 20. What is the largest of these... (answered by richwmiller)
What is the largest possible value for the sum of five consecutive even numbers, if 10... (answered by stanbon)
10.55
Cash withdrawals (in multiples of $20) at an on-campus ATM for a random sample of (answered by stanbon)
The sum of 4 consecutive multiples of 12 have a sum of 216. What is the greatest of these (answered by suruman)
The final mathematics exam at a certain school contains question of equal difficulty, and (answered by greenestamps)
if 30% of 40% of a positive number is equal to 20% of w percent of the same number , what (answered by josmiceli)
300 chocolates are distributed equally among certain group of students if there are 10... (answered by josgarithmetic)
The numbers which divide 80 in such a way that the sum of their reciprocals is
4/75 are... (answered by richwmiller)
1. If a man buys 1 lt of milk for Rs.12 and mixes it with 20% water and sells it for... (answered by edjones)