SOLUTION: In 1880, a man bought some apples at 2 apples for 3 cents and bought the same number of apples at 2 apples for 5 cents. He sold all of the apples at 3 apples for 7 cents. For eac

SOLUTION: In 1880, a man bought some apples at 2 apples for 3 cents and bought the same number of apples at 2 apples for 5 cents. He sold all of the apples at 3 apples for 7 cents. For eac

Algebra.Com

Question 250538: In 1880, a man bought some apples at 2 apples for 3 cents and bought the same number of apples at 2 apples for 5 cents. He sold all of the apples at 3 apples for 7 cents. For each one dozen apples, how much did he gain?
A.2 cents B.3 cents C.4 cents D.6 cents E.8 cents

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
For 12 apples 3*(.03)+3*(.05)=.24
4*(.07)=.28
.28-.24=.04

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