SOLUTION: The area of a rectangle is 80 square feet. The length is 2 feet longer than the width. Find the measure of each.

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Question 243737: The area of a rectangle is 80 square feet. The length is 2 feet longer than the width. Find the measure of each.
Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
We know the area of a rectangle is width times the length.
A+=+W+%2A+L
.
We are told A = 80
.
We also are told L is 2 feet longer than the width.
L+=+W+%2B+2
or
W+=+L+-+2
You pick.
.
Substituting what we know:
A+=+W+%2A+L
80+=+%28L-2%29+%2A+L
Multiplying through the right-hand:
80+=+L%5E2+-+2L
Equal things are equal, so we can rewrite:
L%5E2+-+2L+=+80
Subracting 80 from both sides
L%5E2+-+2L+-+80+=+0
.
We now consider whether it can be factored. The factors of 80 are 2*40, 4*20, 5*18, 8*10...
We have to have different signs to get them to multiply to -80.
And we need them to be 2 apart to have the solve the L term. 8 & 10 is the way to go.
.
%28L-10%29%28L%2B8%29+=+0
.
So we have two candidate solutions: L=10 and L=-8.
Since we are talking about the area of a rectangle, a length of -8 is not reasonable. So we'll test 10.
.
Looking back at the equations we established:
W+=+L+-+2+=+10+-+2+=+8
.
So we propose the L=10 and W=8.
.
Checking the Area, we test:
A+=+L+%2A+W+=+10+%2A+8+=+80
.
That checks. So we're done.