The sum of the digits of a three-digit number is 6. If the hundreds and tens are reversed, the resulting number is 90 more than the original number.If the tens and units digits are reversed,the resulting number is 9 more than the original number. Find the original number
Let h = the hundreds digit
Let t = the tens digit
Let u = the units digit
Then the original number =
The number formed by reversing the hundreds and tens digits =
The number formed by reversing the tens and units digits =
The sum of the digits of a three-digit number is 6.
That says:
If the hundreds and tens are reversed, the
resulting number is 90 more than the original number
That says:
Simplifying:
If the tens and units digits are reversed,the resulting number is 9 more than the original number.
Simplifying:
Solve that and get , , .
So the original number = 123
Checking:
The original number = 123
The number formed by reversing the hundreds and tens digits = 213
The number formed by reversing the tens and units digits = 132.
The sum of the digits of a three-digit number is 6.
1+2+3=6 That checks.
If the hundreds and tens are reversed, the resulting number is 90 more than the original number.
213 is 90 more than 123. That checks
If the tens and units digits are reversed,the resulting number is 9 more than the original number
132 is 9 more than 123. That checks.
So it's correct. The original number is 123.
Edwin