SOLUTION: I need help figuring out the following quadratic word problem, I am totally confused by this problem. Minimum Cost: It costs Acme Manufacturing C dollars per hour to operate

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: I need help figuring out the following quadratic word problem, I am totally confused by this problem. Minimum Cost: It costs Acme Manufacturing C dollars per hour to operate       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 23660: I need help figuring out the following quadratic word problem, I am totally confused by this problem.
Minimum Cost:
It costs Acme Manufacturing C dollars per hour to operate its golf ball division. An analyst has determined that C is related to the number of golf balls produced per hour, x, by the equation C = 0.009x^2 - 1.8x + 100. What number of balls per hour should Acme produce to minimize the cost per hour of manufacturing these golf balls?
Any help or explanation will be greatly appreciated.

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
C = 0.009x^2 - 1.8x + 100
COMBINE X^2 AND X TERMS TO FIT A PERFECT SQUARE
C=0.1{0.09X^2-18X}+100
C=0.1{(0.3X)^2-2*(0.3X)*30+30^2-30^2}+100
C=0.1{(0.3X-30)^2}+100-90
C=0.1{(0.3X-30)^2}+10
HENC C WILL BE MINIMUM IF {(0.3X-30)^2}IS MINIMUM WHICH BEING PERFECT SQUARE WILL BE MINIMUM ZERO WHEN 0.3X=30...OR...X=30/0.3=300/3=100...THAT IS WHEN 100 BALLS ARE MADE PER HOUR....THE MINIMUM COST IS C=10...