SOLUTION: I'd appreciate any help with this, I'm completely stuck! An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which t

Question 233979: I'd appreciate any help with this, I'm completely stuck!
An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 150 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 3 seconds? Round results to the nearest tenth of a meter.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
"h is the height in meters from which the launch occurs"
___ "the top of a building 150 meters tall"

"v is the initial upward speed in meters per second"
___ "initial speed is 35 meters per second"

"t is the number of seconds for which the OBJECT is airborne"
___ "how high above the ground will the pebble be after 3 seconds"

height = 150 + 35(3) - 9.8(3^2)
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