SOLUTION: Bryan can buy candy canes at 4 for 50¢ and can sell them at 3 for 50¢. How many canes must Bryan sell to make a profit of $5.00?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Bryan can buy candy canes at 4 for 50¢ and can sell them at 3 for 50¢. How many canes must Bryan sell to make a profit of $5.00?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 227001: Bryan can buy candy canes at 4 for 50¢ and can sell them at 3 for 50¢. How many canes must Bryan sell to make a profit of $5.00?
Answer by lilmama50(7) About Me  (Show Source):
You can put this solution on YOUR website!
If Bryan buys the candy canes 4 for 50 cents, first figure out what he pays a piece per candy cane by dividing 50 cents by 4. 0.50%2F4=12.5 This gives you 12.5 cents and that's how much he pays per cane.

Now figure out how much he sells each cane for by dividing 50 cents by 3 since thats how he sells them. 0.50%2F3=16.5 This gives you 16.5 cents.

So his profit from each cane can be figured by subtracting how much he buys one for by how much he sells one for: 16.5-12.5=4 So he makes a profit of 4 cents on each candy cane. Since Bryan needs to make a total profit of $5, you can take 5 divided by his profit amount of 4 cents: 5%2F0.04=125 Therefore Bryan must sell 125 candy canes to make a profit of $5.