SOLUTION: How much pure acid should be mixed with 2 gallons of a 50% acid solution in order to get an 80% acid solution?
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Question 225689: How much pure acid should be mixed with 2 gallons of a 50% acid solution in order to get an 80% acid solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.50*2+X=.80(2+X)
1+X=1.6+.8X
X-.8X=1.6-1
.2X=.6
X=.6/.2
X=3 GALLONS OF PURE ACID IS USED.
PROOF:
.50*2+3=.80(2+3)
1+3=.8*5
4=4
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