SOLUTION: (((The Schwarzschild radius describes the critical valie to which the radius of a massive body must be reduced for it to become a black hole. R=2GM/C^2 where G = gravitational c

Question 224864: (((The Schwarzschild radius describes the critical valie to which the radius of a massive body must be reduced for it to become a black hole.
R=2GM/C^2
where
G = gravitational constant 6.7*10^-11
M = mass of the object
C = speed of light 3*10^8
the sun has M = 2*10^30. What is the Schwarzschild radius for the sun? [Note its true radius is 700,000])))
I have been trying to come up with an equation for this and I thought that by plugging in the values as they are in the equation R=2GM/C^2 I could solve the problem. However, I have been having difficulties coming up with a solution. Please help if you can!
Answer by LtAurora(115) (Show Source): You can put this solution on YOUR website!
You are correct, all you have to do is plug in the numbers.

This gives us a Schwarzschild radius of 2977.777 km.
The significance of this number is that if the mass of the sun were contained within 2977.777 km, the sun would continue to collapse into a black hole.
So, you're not trying to get the 700,000 km radius of the sun. They're just giving that to you so you can compare and go "oooo" over the fact that it has to collpase down 697022 km before we've got a black hole at our doorstep.
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