SOLUTION: a hospital needs 80 L of a 12% solution of disinfectant. how many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution?
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Question 221975: a hospital needs 80 L of a 12% solution of disinfectant. how many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.33x+.05(80-x)=.12*80
.33x+4-.05x=9.6
.33x-.05x=9.6-4
.28x=5.6
x=5.6/.28
x=20 L of 33% solution is used.
80-20=60 L of 5% solution is used.
Proof:
.33*20+.05*60=.12*80
6.6+3=9.6
9.6=9.6
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