SOLUTION: If Juan has 4 more than twice the amount of nickels as sam and carlos has 2 less than 3 times the amount of nickels as sam and the total value of all 3 boys is 1.90, than how many

Question 218682: If Juan has 4 more than twice the amount of nickels as sam and carlos has 2 less than 3 times the amount of nickels as sam and the total value of all 3 boys is 1.90, than how many nickels does sam have?
so far i am trying to set up the problem...
s=sam, c=carlos, j=juan
j=2(sam amount)+ 4
c=3(sam amount)-2
total= 1.90
there are 38 nickels...
please help..thanks
Found 2 solutions by josmiceli, MathTherapy:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = number of nickels Juan has
Let = number of nickels Sam has
Let = number of nickels Carlos has
given:
(1)
(2)
(3) (in nickels)
Substitute (1) and (2) in (3)

Sam has 6 nickels
check answer:
and

also

and

OK
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
If Juan has 4 more than twice the amount of nickels as sam and carlos has 2 less than 3 times the amount of nickels as sam and the total value of all 3 boys is 1.90, than how many nickels does sam have?

Let amount of nickels that Sam has be S
Since Juan has 4 more than twice Sam's amount, then Juan has 2S + 4
Since Carlos has 2 less than 3 times Sam's amount, then Carlos has 3S - 2

Together, the 3 boys have: S + 2S + 4 + 3S - 2, or (6S + 2) nickels

Now, since the value of all their nickels is $1.90, then we have:

.05(6S + 2) = 1.9

.3S + .1 = 1.9

.3S = 1.8

Therefore, , which means that Sam has nickels.

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