SOLUTION: Four times the difference of a number and 2 is the same as 2 increased by four times the number plus twice the number. Find the number. How do you solve this? I don't understand

Question 214847: Four times the difference of a number and 2 is the same as 2 increased by four times the number plus twice the number. Find the number. How do you solve this? I don't understand it.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Four times the difference of a number and 2 is the same as 2 increased by four times the number plus twice the number. Find the number.

Step 1. Let n be the number.

Step 2. Let n-2 is the difference between the number and 2.

Step 3. Let 4(n-2) is four times the difference between the number and 2

Step 4. Let 2+4n+2n be 2 increased by 4 times the number plus twice the number

where 4n is four times the number and 2n is twice the number.

Step 5. Set expressions in Step 3 and 4 equal.

Subtract 4n to both sides of the equation

Subtract -2 to both sides of the equation to get solve for n

Divide by 5 to both sides of equation to get n

Step 6. ANSWER. The number is -5.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J
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