SOLUTION: #20
FIND THREE CONSECUTIVE ODD INTEGERS SUCH THAT FOUR TIMES THE MIDDLE INTEGER IS TWICE THE SUM OF THE OTHER TWO INTEGERS
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Question 213411: #20
FIND THREE CONSECUTIVE ODD INTEGERS SUCH THAT FOUR TIMES THE MIDDLE INTEGER IS TWICE THE SUM OF THE OTHER TWO INTEGERS
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
FIND THREE CONSECUTIVE ODD INTEGERS SUCH THAT FOUR TIMES THE MIDDLE INTEGER IS TWICE THE SUM OF THE OTHER TWO INTEGERS
Step 1. Let n be an odd integer, n+2 be the next consecutive odd or middle integer, and n+4 be the second consecutive odd integer
Step 2. 4(n+2)=2(n+n+4) since middle integer is twice the sum of n+n+4
Step 3. The above result means any 3 consecutive odd integers will satisfy the above equation or problem statement. For example,
1, 3, 5 implies 4(3)=2(1+5) or 12=12
3, 5, 7 implies 4(5)=2(3+7) or 20=20
5, 7, 9 implies 4(7)=2(5+9) or 28=28
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
Good luck in your studies!
Respectfully,
Dr J
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