SOLUTION: If the width of a rectangle is 1 inch less than its length and the diagonal is 1 inch longer than its length, find the length and the width.

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Let,,,Length = L
Width = L-1
Diagonal = L+1
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Diagonal is hypotenuse of a right triangle, therefore use the pythagorian theorem,
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c^2 = a^2 + b^2
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(L+1)^2 = (L)^2 + (L-1)^2
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L^2 +2L +1 = L^2 + L^2 -2L +1
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L^2 - 4L =0
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L (L-4) =0
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L=4,,,,0 (not realistic)
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L=4, W=3, Dia = 5
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check,,5^2 = 3^2 + 4^2 ,,,,,ok
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