SOLUTION: Sam is 10 years older than Jack. Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age. Find Jack and Sam's age.

Question 210426: Sam is 10 years older than Jack. Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age. Find Jack and Sam's age.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Sam is 10 years older than Jack.
Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age.
Find Jack and Sam's age.
:
Let j = Jack's age
Let s = Sam's age
:
"Sam is 10 years older than Jack."
s = j + 10
:
"Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age."
6j - 2s = j + 7
6j - j = 2s + 7
5j = 2s + 7
:
Find Jack and Sam's age.
:
Substitute (j+10) for s in the above equation
5j = 2(j+10) + 7
5j = 2j + 20 + 7
5j - 2j = 27
3j = 27
j =
j = 9 yrs is Jack's age
:
s = j + 10
s = 9 + 10
s = 19 yrs is Sam's age
:
:
Check solution in the statement:
"Twice Sam's age subtracted from 6 times Jack's age is 7 more than Jack's age."
-2(19) + 6(9) = 9 + 7
-38 + 54 = 16
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