SOLUTION: If 1 ≤ a ≤ 10 and 1 ≤ b ≤ 36, for how many ordered pairs of integers (a, b) is
square root ( a + square root b) an integer?
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Question 203335:  If 1 ≤ a ≤ 10 and 1 ≤ b ≤ 36, for how many ordered pairs of integers (a, b) is
square root ( a + square root b) an integer? 
Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
 In order for  to be an integer,  must be a perfect square. And for  to be a perfect square,  must be an integer. And finally, in order for  to be an integer, b must be a perfect square.
So we'll start by checking possible values for "b": perfect squares between 1 and 36 (inclusive). And we will then see if we can find an "a", between 1 and 10 (inclusive) which makes the rest of the expression work out as desired.- "b" is 1- "a" = 3 works: 
- "a" = 8 works: 
 
- "b" = 4- "a" = 2 works: "a" = 7 works
 
"b" = 9- "a" = 1 works: 
- "a" = 6 works: 
"b" = 16"b" = 25"b" = 36
So the solutions as ordered pairs:
(3, 1)
(8, 1)
(2, 4)
(7, 4)
(1, 9)
(6, 9)
(5, 16)
(4, 25)
(3, 26) 
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