SOLUTION: The intensity of illumination on a surface varies inversely as the square of the distance of the light from the surface. If the illumination from a source is 64 foot candles when t
Algebra.Com
Question 202901: The intensity of illumination on a surface varies inversely as the square of the distance of the light from the surface. If the illumination from a source is 64 foot candles when the distance is 9 feet, then find the illumination when the distance is 12 feet. Would it be 6, 8, 32 or 36 foot candles. Could someone please help me with this been trying but need some assistance, thanks.
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Intensity changes inversely with distance squared
You are given . Thus
RELATED QUESTIONS
the intensity I of light varies inversely as the square of the distance D from the source (answered by rothauserc,greenestamps)
The intensity I of light varies inversely as the sqaure of the distance D from the... (answered by ankor@dixie-net.com)
The illumination (in foot-candles) of a light source varies directly as the intensity... (answered by stanbon)
The intensity of light on the plane surface varies inversely as the square of the... (answered by TimothyLamb)
The intensity of light on the plane surface varies inversely as the square of the... (answered by Theo)
The intensity I of light varies inversely as the square of the distance D from the... (answered by Earlsdon)
The intensity of a light varies inversely as the square of the distance from the light... (answered by ewatrrr)
the intensity of illumination from a source of light varies inversely as the square of... (answered by rothauserc)
The intensity of light varies inversely as the square of the distance from the light... (answered by Alan3354)