SOLUTION: A painting canvas has a length 8 inches longer than its width. If the area is 84 in^2, what are the dimensions of the canvas?
A) 16 inches by 6 inches
B) 15 inches by 7 inches
Algebra.Com
Question 199764: A painting canvas has a length 8 inches longer than its width. If the area is 84 in^2, what are the dimensions of the canvas?
A) 16 inches by 6 inches
B) 15 inches by 7 inches
C) 13 inches by 5 inches
D) 14 inches by 6 inches
Found 2 solutions by solver91311, rfer:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the width, then 
represents the length, so:
 = 84)
Distribute, put into standard form, and then solve the resulting quadratic. Exclude the negative root. The positive root is the width and the length is 8 more inches.
Alternatively, you could calculate the area represented by each of the pairs of dimensions given in the 4 choices and select the one that results in 84 square inches.
John
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
D) (6)(6+8)=84
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