SOLUTION: Hi, I am having trouble figuring out this problem. Would someone please help me figure out the formula? Thank you. The height in feet for a ball thrown upward at 48 feet per s

Question 197762: Hi, I am having trouble figuring out this problem. Would someone please help me figure out the formula? Thank you.
The height in feet for a ball thrown upward at 48 feet per
second is given by s(t)=-16t^2+48t, where t is the time
in seconds after the ball is tossed. What is the maximum
height that the ball will reach?
Equation of motion of the ball is
It is the equation of a parabola.
So the maximum height will be at its vertex.
Vertex = (,)
-------(1)
--------(2)
Comparing (1) and (2)

== 1.5
=36
So the maximum height the ball will reach is 36 feet

Answer by mathsteacher(28) (Show Source): You can put this solution on YOUR website!

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