SOLUTION: A Special rubber ball is dropped from a height of 128 meters . Each time the ball bounces to half its previous height. After 1 bounce the ball reaches a height of 64 meters. a.

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: A Special rubber ball is dropped from a height of 128 meters . Each time the ball bounces to half its previous height. After 1 bounce the ball reaches a height of 64 meters. a.       Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Question 195215: A Special rubber ball is dropped from a height of 128 meters . Each time the ball bounces to half its previous height. After 1 bounce the ball reaches a height of 64 meters. a. How high did the ball reach after the 7th bounce. b.How high does the ball get after the 9th bounceAnswer by windsolace(8)   (Show Source): You can put this solution on YOUR website!The series identified is a geometric progression with common ratio of half. Formula for geometric progression: Nth term of series = ar^(n-1), where a = first term value, r = common ratio a) 7th term of the series = 64(1/2)^(7-1) = 64(1/2)^6 = 64(1/64) = 1 The ball reached a height of 1m after the 7th bounce b) 9th term of series = 64(1/2)^8 = 64/256 = 0.250 The ball reached a height of 0.25m (25cm) after the 9th bounce.