SOLUTION: A population is increasing at 6% per year and is now at 12,000. If it continues to increase at the same rate, approximately how long will it take to reach 15,000? Round to the nea
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Question 194319This question is from textbook saxon algebra 2
: A population is increasing at 6% per year and is now at 12,000. If it continues to increase at the same rate, approximately how long will it take to reach 15,000? Round to the nearest tenth of a year.
I figured it out to be 4.2 years. Am I right? This question is from textbook saxon algebra 2
You can put this solution on YOUR website! A population is increasing at 6% per year and is now at 12,000. If it continues to increase at the same rate, approximately how long will it take to reach 15,000? Round to the nearest tenth of a year.
I figured it out to be 4.2 years. Am I right?
:
That's not what I got, here's how I would do it:
:
Let t = no. of yrs for this to happen
:
12000(1.06^t) = 15000
1.06^t =
1.06^t = 1.25
Using logs
t*log(1.06) = log(1.25)
:
.0253t = .0969
t =
t = 3.83 ~ 3.8 yrs
;
;
Check solution on calc
enter: 12000 * 1.06^3.83 = 15000