SOLUTION: i have no clue how to work these find coordinates of the vertex and the equation of the directrix of the parabola (x-6)^2= -12(y+2) thanks

Question 189397: i have no clue how to work these
find coordinates of the vertex and the equation of the directrix of the parabola (x-6)^2= -12(y+2)
thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
i have no clue how to work these
find coordinates of the vertex and the equation of the directrix of the parabola (x-6)^2= -12(y+2)
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Do you see that if you let x=6, y would be -2 ?
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That is the vertex: (6,-2)
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Using the form (x-h)^2 = 4p(y-k) you should see that
4p = -12
p = -3.
So the directrix is 3 below the vertex.
Directrix is y = -5
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Cheers,
Stan H.
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