SOLUTION: One train leaves a station heading west. Two hours later a second train leaves the same station heading east. The second train is traveling 15 mi/h fast than the first. Six hours a

Question 186372: One train leaves a station heading west. Two hours later a second train leaves the same station heading east. The second train is traveling 15 mi/h fast than the first. Six hours after the second train leaves, the two trains are 580 miles apart. Find the rate of which each train is traveling
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
rt=d
r(6+2)+(r+15)6=580
r*8+6r+90=580
8r+6r=580-90
14r=490
r=490/14
r=35 mph. is the speed of the slower train.
35+15=50 mph. is the speed of the faster train.
Proof:
35*8+50*6=580
280+300=580
580=580
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