SOLUTION: Find three consecutive positive even integers such that the sum of their squares is 980.
Algebra.Com
Question 181922: Find three consecutive positive even integers such that the sum of their squares is 980.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find three consecutive positive even integers such that the sum of their squares is 980.
----------------
There are 2 ways to do this.
The easy way:
Since the numbers are close, each is about 1/3 of the total.
980/3 =~ 326. The square root of 326 is just over 18 (18^2 = 324).
So 18 is the middle number, and they're 16, 18 and 20.
-------------------
The hard way:
(3x+60)*(x-16) = 0
x = 16, x = -20
It says positive, so it's 16, 18 & 20
RELATED QUESTIONS
Find three consecutive positive odd integers such that the sum of their squares is... (answered by ramkikk66,mananth,Alan3354)
The sum of the squares of three consecutive even integers is 980. Find the integers.... (answered by ikleyn)
Consecutive Integers. Find three consecutive integers such that the sum of their squares... (answered by checkley77)
find two consecutive positive even numbers such that the sum of their squares is 164. (answered by Alan3354)
Find the bigger 2 consecutive positive integers such that the sum of their squares is... (answered by Alan3354)
Find two consecutive positive integers such that the sum of their squares is 85. (answered by xcentaur)
Find two consecutive positive integers such that the sum of
their squares is... (answered by Nate)
Find two consecutive positive integers such that the sum of their squares is... (answered by checkley71)
Number problems. Find two consecutive positive integers such that the sum of their... (answered by checkley75)