SOLUTION: the length of a rectangle is 5 feet more than it's width. the area of the rectangle is 176 sq ft. find the length and the width of the rectangle

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Question 179357: the length of a rectangle is 5 feet more than it's width. the area of the rectangle is 176 sq ft. find the length and the width of the rectangle
Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
the length of a rectangle is 5 feet more than it's width. the area of the rectangle is 176 sq ft. find the length and the width of the rectangle
:
A=L*W......eq 1
L=W+5......eq 2
A=176......eq 3
:
take L's value of W+5 from eq 2 and A's value of 176 and plug them into eq 1
:
176=(W+5)W
:

:

:
W=11 and -16...throw out the negative value
:
width
:
length
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=729 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 11, -16. Here's your graph:
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