SOLUTION: 46. find the values of sinu/2 cosu/2 tanu/2 cosu=3/5

Question 174458: 46. find the values of sinu/2 cosu/2 tanu/2
cosu=3/5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the values of [sin(u) / 2cos(u)] / [2tan(u) / 2cos(u)] =3/5
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Invert the denominator and multiply:
[sin(u) / 2cos(u)] * [2cos(u)/2tan(u)] =3/5
Simplify:
[(1/2)tan(u)] * [2cos(u)/2tan(u)] =3/5
Cancel the common factors of 2 and tan(u) to gt:
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[(1/2)] * [cos(u)/1] = 3/5
cos(u) = 6/5
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But cos values must be between -1 and +1.
Conclusion: No solution
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Cheers,
Stan H.

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