SOLUTION: A house had two rooms of equal area. One room is square and the other roon is a rectangle 4ft narrower and 5ft longer than the square one. Find the area of each room.

Question 174169: A house had two rooms of equal area. One room is square and the other roon is a rectangle 4ft narrower and 5ft longer than the square one. Find the area of each room.
Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let x=side length of square

Since "A house had two rooms of equal area. One room is square and the other room is a rectangle 4ft narrower and 5ft longer than the square one.", this means that

Start with the given equation.

FOIL

Subtract from both sides.

Combine like terms.

Add 20 to both sides.

So the answer is which means that the side length of the square is 20 ft. So the area of the square is square feet.

So the length of the rectangle is ft and the width is ft. So the area of the rectangle is square feet.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
areas are equal

let x=side of square room

x^2 = (x-4)(x+5)

x^2 = x^2 + x - 20

subtracting x^2-20 __ 20 = x

one room is 20x20 and the other is 16x25
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