SOLUTION: The decay rate of krypton-85 is 6.3% per day. What is the half-life? Using the exponential decay function P(t) =Po^e^-kt

Question 173430This question is from textbook introduction to college mathematics
: The decay rate of krypton-85 is 6.3% per day. What is the half-life?
Using the exponential decay function P(t) =Po^e^-kt This question is from textbook introduction to college mathematics

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The decay rate of krypton-85 is 6.3% per day. What is the half-life?
Using the exponential decay function P(t) =Po^e^-kt
:
The exponential decay formula that I am familiar with:
A = Ao[2^(-t/h)]
where
Ao is the initial amt
A = final amt
t = time
h = half-life of the substance
:
Assume Ao = 100, Assume t = 1 day, find h (half life in days)
After 1 day, A = 100 - 6.3 = 93.7
:
100 * 2^(-1/h) = 93.7
:
2^(-1/h) =
:
2^(-1/h) = .937
:
ln[2^(-1/h)) = ln(.937)
:
*.693 = -.065
:
= -.065
:
h =
h = 10.66 days is the half life of krypton-85 according to this information
:
In actual fact I think they mean 6.3% per year, hence, 10.66 yrs half life
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