SOLUTION: Please help me solve this equation: A ball is thrown upward with an initial velocity of 30 feet per second from a point that is 24 feet above the ground. The height h (in fe

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Question 173046: Please help me solve this equation:
A ball is thrown upward with an initial velocity of 30 feet per second from a point that is 24
feet above the ground. The height h (in feet) of the ball at time t (in seconds) after it is
thrown is
h= -16t^2 + 30t + 24
Find the time when the ball hits the ground.
Answer by KnightOwlTutor(293)   (Show Source): You can put this solution on YOUR website!
Set the equation to 0. When the ball hits the ground the distance is 0. Then use the quadratic formula.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=2436 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.604870334906633, 2.47987033490663. Here's your graph:
t=2.8
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